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If we translate the LTL to Lo1, will it also satisfy the translation to Lo2? if not then what is the valid way of translation to Lo2?

in * TF "Emb. Sys. and Rob." by (1.4k points)

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LO1 is the subset of LO2 that does not make use of second order quantification. Hence, any LO1 formula is also a LO2 formula, and therefore a translation from LTL to LO1 is also a (special) translation from LTL to LO2.
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Thanks so in the exam will LO1 translation for a given LTL be accepted?
If the question is to translate the given LTL formula to LO1 or LO2, the answer is yes, since LO1⊂LO2.
understood thanks.

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