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In q => !q' | (q' <-> b), => does not seem to be same as -> (implies) condition.

in * TF "Emb. Sys. and Rob." by (140 points)

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(c => p1 | p0) means "if c then p1 else p0", i.e., c&p1 | !c&p0 (see Chapter on Propositional logic, page 4).
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