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Conversion to CTL

0 votes

Is this the right Conversion?

in * TF "Emb. Sys. and Rob." by (160 points)

1 Answer

0 votes

It is not correct: (GFb & FXb) is not equivalent to F(Gb & Fb); why do you believe that it is so?

A correct computation would be as follows

    !A(GXFb & FXb)
    = !A(GFXb & FXb)
    = !A(GFXb)
    = !AGFb
    = !AGAFb
    =  EFEG!b
by (162k points)

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