Here you can ask questions and find or give answers to organizational, academic and other questions about studying computer science.

1.1k questions

1.2k answers

1.6k comments

543 users

From paper 2019.02.13 Problem 2(a)

How did we go from (!b & c ^c ) to (b&c)?Since and binds stronger than XOR.

I solved it as (!b & c ^c ) (distribution) -> (!b & c) ^ (!b&c) -> 0. T^T or F^F = 0

!b&c xor c = (c ? !b&1 xor 1 : !b&0 xor 0) = (c ? !b xor 1 : 0 xor 0) = (c ? b : 0) = b&c