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Quantifier free CNF/DNF [closed]

0 votes

2018.02.14

This questions asks that at the end we are supposed to convert our result into a quantifier free CNF/DNF. I did not understand what that means, especially the last 2 steps

=>a & !(p | (p & q))=>a&!p

How is "q" removed at the end? 

closed with the note: I understood the final step.
in * TF "Emb. Sys. and Rob." by (1k points)
closed by

1 Answer

0 votes
I understood the final step simplification now. I will close this question.
by (1k points)

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