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No, it is not, but you can compute that as follows:
EGE((Fb)&(Fa)) = EGE( (F(b&(Fa))) | (F(a&(Fb))) ) = EG( (EF(b&(Fa))) | (EF(a&(Fb))) ) = EG( (EF(b&(EFa))) | (EF(a&(EFb))) )