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Exam problem : 14.02.2018 8 (f) : * (

I just want to clarify about my understanding.

I came up with below solution which satisfies S2 and not S1 :

In S2, [a WB b] should hold because a is true in first place and hence as [a WB b] is true so the whole formula is true as c never holds.

In S1, a is true at first and as b and c never holds so in weak before [0 WB 0] results in true and hence both a and [b WB c] coexist hence it is not satisfied.

I also checked with tool :

G (a&!b&!c) -> (([[a WB b] WB c]) & !([a WB [b WB c]]))  results Valid.

But I just wanted to know whether my understanding as described as above is correct or not.

Thanks in advance 

in * TF "Emb. Sys. and Rob." by (2.9k points)

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You are right with all you wrote. Perfect!
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Thanks a lot for the verification.

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