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This is my solution to this question but it's different from the solution provided by you. Would you please tell me what I did wrong?

in * TF "Emb. Sys. and Rob." by (1.7k points)

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Surprisingly that question and problem appeared already in another question. It seems that you are reading (a => b | c) as an implication of a disjunction. However, it is the Shannon operator and mans if-then-else, i.e., (a=>b|c) is equivalent to (a->b) & (!a->c). It is not (a->b|c).
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